Решение ненравенств с одной переменной.
Answer (2)
[tex]\displaystyle\bf\\x\cdot(7+5)\leq 36\\\\\\x\cdot 12\leq 36 \ |: \ 12\\\\\\x\leq 3\\\\\\x\in\Big(-\infty \ ; \ 3\Big][/tex]
Х * ( 7 + 5) ≤ 36(7 + 5) = 1212 * X ≤ 36 | : 12X ≤ 3X ∈ ( - ∞; 3]
[tex]\displaystyle\bf\\x\cdot(7+5)\leq 36\\\\\\x\cdot 12\leq 36 \ |: \ 12\\\\\\x\leq 3\\\\\\x\in\Big(-\infty \ ; \ 3\Big][/tex]
Х * ( 7 + 5) ≤ 36(7 + 5) = 1212 * X ≤ 36 | : 12X ≤ 3X ∈ ( - ∞; 3]
