In Алгебра / студенческий | 2025-08-24
Asked by tidisa9022
Ответ: f'(x) = 12x² - 6xОбъяснение:f(x) = 4x³ - 3x² - 2f'(x) = (4x³ - 3x² - 2)'f'x) = (4x³)' + (-3x²)' - (2)'f'(x) = 4 * 3x² - 3 * 2x - 0f'(x) = 12x² - 6x
Answered by fedorsolovyev | 2025-08-24